2x^2+33x+72=0

Solution for 2x^2+33x+72=0 equation:

2x^2+33x+72=0

a = 2; b = 33; c = +72;
Δ = b2-4ac
Δ = 332-4·2·72
Δ = 513
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{513}=\sqrt{9*57}=\sqrt{9}*\sqrt{57}=3\sqrt{57}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-3\sqrt{57}}{2*2}=\frac{-33-3\sqrt{57}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+3\sqrt{57}}{2*2}=\frac{-33+3\sqrt{57}}{4}
$